Question
Physics Question on Electrostatic potential
Potential energy of two charges 10nC each separated by a distance of 0.09 m in air is
A
10μJ
B
1μJ
C
10mJ
D
10J
Answer
10μJ
Explanation
Solution
Potential energy of two charge system is given by
U=4πe0er1×rq1q2
Here, q1=q2=10nC=10×10−9C
4πe01=9×109Nm2C−2r=r=0.09m
∴U=9×109×0.0910×10−9×10×10−9=10μJ