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Question

Question: Potential energy of a satellite having mass ‘m’ and rotating at a height of \(6.4 \times 10 ^ { 6 }\...

Potential energy of a satellite having mass ‘m’ and rotating at a height of 6.4×1066.4 \times 10 ^ { 6 }m from the earth centre is

A

0.5mgRe- 0.5 m g R _ { e }

B

mgRe- m g R _ { e }

C

2mgRe- 2 m g R _ { e }

D

4mgRe4 m g R _ { e }

Answer

mgRe- m g R _ { e }

Explanation

Solution

Potential energy =GMmr= - \frac { G M m } { r } =GMmRe+h= - \frac { G M m } { R _ { e } + h } =GMm2Re= - \frac { G M m } { 2 R _ { e } }

[As h=Reh = R _ { e } (given)]

∴ Potential energy =gRe2m2Re= - \frac { g R _ { e } ^ { 2 } m } { 2 R _ { e } } =0.5mgRe= - 0.5 m g R _ { e }

[As GM=gR2G M = g R ^ { 2 } ]