Question
Physics Question on Kirchhoff's Laws
Potential difference between A and B in the following circuit
A
4 V
B
5.6 V
C
2.8 V
D
6 V
Answer
5.6 V
Explanation
Solution
Apply Kirchhoff's second loop law, go from A to B anti-clockwise
I(2+8)=6−4
I⋅10=2
I=0.2A
VA−I×2+6=VB
VA−VB=0⋅2×2−6
=0.4−6=−5.6V
Hence, VA<VB
and VBA=5.6V