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Question

Physics Question on Kirchhoff's Laws

Potential difference between AA and BB in the following circuit

A

4 V

B

5.6 V

C

2.8 V

D

6 V

Answer

5.6 V

Explanation

Solution

Apply Kirchhoff's second loop law, go from AA to BB anti-clockwise
I(2+8)=64I(2+8) =6-4
I10=2I \cdot 10 =2
I=0.2AI =0.2 A
VAI×2+6=VBV_{A}-I \times 2+6 =V_{B}
VAVB=02×26V_{A}-V_{B} =0 \cdot 2 \times 2-6
=0.46=5.6V=0.4-6=-5.6 \,V
Hence, VA<VBV_{A} < V_{B}
and VBA=5.6VV_{B A}=5.6 \,V