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Pharmaceutical Analysis Question on Oxidation-reduction titrations

Potential at the equivalence point for a redox reaction
aOX1+bRED2⇌bOX2+aRED1\mathrm{aOX1} + \mathrm{bRED2} \rightleftharpoons \mathrm{bOX2} + \mathrm{aRED1}
is given by the equation:

A

E=(bE10+aE20)(a+b)E=\frac{(bE_1^0+aE_2^0)}{(a+b)}

B

E=E0+(0.0592n)XlogQE=E^0+(\frac{0.0592}{n})X logQ

C

E=E0+(0.0592n)Xlog(RedOX)E=E^0+(\frac{0.0592}{n})X log(\frac{Red}{OX})

D

E=E10+E202E=E_1^0+\frac{E_2^0}{2}

Answer

E=(bE10+aE20)(a+b)E=\frac{(bE_1^0+aE_2^0)}{(a+b)}

Explanation

Solution

The correct option is (A):E=(bE10+aE20)(a+b)E=\frac{(bE_1^0+aE_2^0)}{(a+b)}