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Physics Question on Polarisation

Polarising angle for water is 53∘^{\circ}4'. If the light is incident at this angle on the surface of the water and reflected the angle of refraction is

A

53∘^{\circ}4'

B

26∘^{\circ}56'

C

36∘^{\circ}56'

D

30∘^{\circ}4'

Answer

36∘^{\circ}56'

Explanation

Solution

Here, θp+r=90∘\theta p+r=90^{\circ}
⇒r=90∘−θp\Rightarrow r=90^{\circ}-\theta p
⇒r=90∘−53∘4′\Rightarrow r=90^{\circ}-53^{\circ}4'
=36∘56′=36^{\circ}56'