Question

Point of contact where line 4x + 3y – 6 = 0 is tangent to circle x² + y² + 6y = 0 is

• A. (3/2, 0)
• B. (0, 2)
• C. (0, 0)
• D. $\left( \frac { 12 } { 5 } , \frac { - 6 } { 5 } \right)$

Answer 1

Answer: (D)

$\left( \frac { 12 } { 5 } , \frac { - 6 } { 5 } \right)$

Answer 2

Let point of contact is (h, k) then tangent at this point

xh + ky + 3(y + k) = 0

or hx + (k + 3)y + 3k = 0

Compare with 4x + 3y – 6 = 0

Ž h = $\frac { 12 } { 5 }$ , k = –$\frac { 6 } { 5 }$