Question
Question: Point (a<sup>2</sup>, a + 1) lies between the angles of the lines 3x – y + 1 = 0 and x + 2y – 5 = 0...
Point (a2, a + 1) lies between the angles of the lines
3x – y + 1 = 0 and x + 2y – 5 = 0 which contains origin if-
A
(–4, –3]
B
(–3, 0) Č (1/3, 1)
C
(5/3, 7/2)
D
(5/2, 3)
Answer
(–3, 0) Č (1/3, 1)
Explanation
Solution
Using 3a2 – (a + 1) + 1 > 0 & a2 + 2(a + 1) – 5 < 0