Question
Question: \((p\mspace{6mu} \land \sim q) \land (\sim p \vee q)\) is...
(p6mu∧∼q)∧(∼p∨q) is
A
A contradiction
B
A tautology
C
Either (1) or (2)
D
Neither (1) nor (2)
Answer
A contradiction
Explanation
Solution
| p | q | ~p | ~q | p∧~q | ~p∨q | (p∧ |
| T | T | F | F | F | T | F |
| T | F | F | T | T | F | F |
| F | T | T | F | F | T | F |
| F | F | T | T | F | T | F |
Clearly, (p6mu∧∼q)∧(p6mu∨∼q) is a contradiction.