Question

Plotting $\frac{1}{Λ_{m}}$ against $cΛ_{m}$ for aqueous solutions of a monobasic weak acid (HX) resulted in a straight line with y-axis intercept of P and slope of S. The ratio $\frac{P}{S}$ is
[$Λ_{m}$ = molar conductivity,
$Λ^{o}_{m}$= limiting molar conductivity,
$c$ = molar concentration,
$K_{a}$ = dissociation constant of HX]

• A. $K_a Λ^o_m$
• B. $K_a \frac{Λ^o_m}{2}$
• C. $2 K_a Λ^o_m$
• D. $\frac{1}{(K_a Λ^o_m)}$

Answer 1

Answer: (A)

$K_a Λ^o_m$

Answer 2

Correct option is (A) Ka Λ°m.

When plotting 1/Λ m ​ against c Λ m ​ for aqueous solutions of a monobasic weak acid (HX), a linear relationship is observed, yielding a straight line with a y-axis intercept of P and a slope of S. The ratio P /S can be represented as:

0 P /S =Ka ​1​+Λ m 0​

Where:

• Λ m ​ is the molar conductivity,
• Λ m 0​ is the limiting molar conductivity,
• c is the molar concentration,
• Ka ​ is the dissociation constant of HX.