Question
Physics Question on Simple Harmonic Motion and Uniform Circular Motion
Plot the corresponding reference circle for each of the following simple harmonic motions. Indicate the initial (t = 0) position of the particle, the radius of the circle, and the angular speed of the rotating particle. For simplicity, the sense of rotation may be fixed to be anticlockwise in every case: ( x is in cm and t is in s).
- x = –2 sin (3t + 3π)
- x = cos (6π – t)
- x = 3 sin (2πt + 4π)
- x = 2 cos πt
a. x =−2sin(3t+3π)+2cos(3t+3π+2π)
= 2cos(3t+65π)
If this equation is compared with the standard SHM equation x =Acos(T2πt+ϕ) , then we get:
Amplitude, A = 2cm
Phase angle, ϕ = 65π=150º
Angular velocity, ω = T2π=3rad/sec.
The motion of the particle can be plotted as shown in the following figure.
x =cos(6π−t)=cos(t−6π)
If this equation is compared with the standard SHM equation x =Acos(T2πt+ϕ), then we get :
Amplitude, A =1
Phase angle, ϕ = −6π=−30º
Angular velocity, ω = T2π=1rad/s
The motion of the particle can be plotted as shown in the following figure.
x = 3sin(2πt+4π)
=−3cos[(2πt+4π)+2π]=-3cos(2πt+43π)
If this equation is compared with the standard SHM equation x = Acos(T2πt+ϕ) , then we get:
Amplitude, A = 3cm
Phase angle, ϕ = 43π=135º
Angular velocity, ω =T2π = 2πrad/s
The motion of the particle can be plotted as shown in the following figure.
x = 2cosπt
If this equation is compared with the standard SHM equation we get: Acos(T2πt+ϕ) then we get:
Amplitude, A = 2cm
Phase angle, ϕ = 0
Angular velocity, ω = πrad/s
The motion of the particle can be plotted as shown in the following figure.