Question

Plates A and B constitute an isolated, charge parallel plate capacitor. The inner surface of A and B have charges $+ Q$ and $-Q$ respectively. A third plate C with charge $+ Q$ is now introduced midway between A and B. Which of the following statements is not correct?

A.The surfaces $I$ and $II$will have equal and opposite charges.
B.The surfaces $III$and $IV$will have equal and opposite charges.
C.The charge on surface $III$will be greater than $Q$.
D.The potential difference between A and C will be equal to the potential difference between C and B.

Answer 1

the comparison of the number of protons and electrons gives a charge.
If there is more proton then it is net positive charge.
If there is more electrons then it is a new negative charge.

Complete answer:
The electric potential is known as the work done on moving charges. It measures the change in the potential energy of a particular charge. We can measure the electric potential units of joules per coulomb and it measures the amount of work per charge.
The capacitance describes the ability to store the charges. The work required to move the positive charge is also known as the electric potential. The capacitance has medical applications like defibrillators. The capacitance is also called a temporary battery.
When there is an excess charge on the insulator or a conductor then the potential field is created around the it. Which is known as the scalar field. The static electric field is a negative
Finally, the field distribution is,

Hence the correct answer is an option (D) The potential difference between A and C will be equal to the potential difference between C and B.

Note:
The electric potential and capacitance have more applications in power generation.
It has a wide range of applications in energy storage also.
We found this electric potential is from the human brain also it is about $70mV$ average.