Question

$pK_a$ of $CH_3COOH$ is 4.74. The pH of 0.01 M $CH_3COONa$ is

• A. 4.74
• B. 8.37
• C. 9.48
• D. None of these

Answer 1

Answer: (B)

8.37

Answer 2

$CH_{3}COONa$ is a salt of a weak acid and strong base $\therefore PH =7+\frac{1}{2}[PK_{a}+log\,C]$ $=7+\frac{1}{2} [4.74+log\,0.01]$ $=7+\frac{1}{2} [4.74-2]$ $=8.37$