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Question

Chemistry Question on Equilibrium

pKapK_a of a weak acid (HA) and pKbpK_b of a weak base (BOH) are 3.23.2 and 3.4,3.4, respectively. .The pH of their salt (AB) solution is :

A

7

B

1

C

7.2

D

6.9

Answer

6.9

Explanation

Solution

pH=7+12(pKapKb)pH=7+\frac{1}{2}\left(pK_{a}-pK_{b}\right) =7+12(3.23.4)=7+\frac{1}{2}\left(3.2-3.4\right) =6.9=6.9