Question

Pitch of screw gauge is 1mm and it has 100 divisions on circular scale. There is no zero error. Thickness of a pile of 50 papers is to be found out. While measuring the thickness of a paper it is observed that linear scale does not give any reading but 25th circular scale division coincides with reference line. Thickness of pile is –

• A. (a) 15.2 mm
• A. (b) 23.5 mm
• A. (c) 21.5 mm
• A. (d) 12.5 mm

Answer 1

(d)

Sol. LC = $\frac { 1 } { 100 }$ = .01 mm

thickness of a paper = 0 + 25 × .01 = .25 mm

thickness of pile = 0.25 × 50 = 12.5 mm