Question

Pitch of screw gauge is 0.5 mm. Circular scale has 250 divisions. While measuring the diameter of a wire the linear scale reads 15 divisions and 100 divisions coincides with reference line of linear scale. Then least count of the screw gauge is –

• A. 0.005 mm
• B. 0.0025 mm
• C. 0.100 mm
• D. 0.002 mm

Answer 1

Answer: (D)

0.002 mm

Answer 2

LC = $\frac { 0.5 \mathrm {~mm} } { 250 }$ = .002 mm