Question

Pitch of screw gauge is 0.5 mm and there are 50 divisions on circular scale. While measuring the diameter of wire it is observed that linear scale reads 2mm and 46^th division of circular scale coincides with reference line. Diameter of wire is –

• A. 0.426 mm
• B. 0.642 cm
• C. 0.426 cm
• D. 0.24 cm

Answer 1

Answer: (D)

0.24 cm

Answer 2

LC = $\frac { 0.5 } { 50 }$ = .01 mm

d = 2 + 46 × .01 = 2.46 mm = 0.246 cm