Question

Pitch of a screw gauge is 0.5 mm and its least count is .01 mm. Calculate no. of divisions on its head scale.

• A. 100
• B. 25
• C. 50
• D. None of these

Answer 1

Answer: (C)

50

Answer 2

Pitch = 0.5 mm

LC = $\frac { \text { Pitch } } { \text { No. of circular scale divisions } }$

\ No of circular scale divisions = $\frac { 0.5 } { .01 } = 50$