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Question

Mathematics Question on Definite Integral

ππ2x(1+sinx)1+cos2xdx∫_{-\pi}^{\pi} \frac{2x(1+sinx)}{1+cos^2x}dx is equal to?

A

π2π^2

B

2π

C

3π2\frac{3π}2

D

π22\frac{π^2}2

Answer

π2π^2

Explanation

Solution

The Correct answer is option is (A) : π2π^2