Question

Phthalimide is made to undergo following sequence of reactions.Total number of $\pi$ bonds present in product 'P' is/are ______

Answer 1

Phthalimide undergoes the following transformations:
In the presence of KOH, the acidic hydrogen of phthalimide is removed, forming the phthalimide anion.
The phthalimide anion then reacts with benzyl chloride via an S$_N2$ reaction, leading to the formation of product 'P'.
In product 'P':
The benzene ring contributes $3 \, \pi$-bonds.
Each carbonyl group (C=O) provides $2 \, \pi$-bonds, giving a total of $4 \, \pi$-bonds for both groups.
The benzyl group attached to nitrogen contributes $1$ additional $\pi$-bond.
Thus, the total number of $\pi$-bonds in product 'P' is:
$3 + 2 + 2 + 1 = 8$