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Question: Photoelectron are emitted with maximum kinetic energy E from a metal surface when light of frequency...

Photoelectron are emitted with maximum kinetic energy E from a metal surface when light of frequency υ falls on it when light of frequency υ' falls on the same metal, the max. KE. Of emitted Photoelectrons is found to be 2E then υ' is –

A

υ1 = υ

B

υ1 = 2υ

C

υ1> 2υ

D

υ1< 2υ

Answer

υ1> 2υ

Explanation

Solution

KE = hυ + φ …..(i)

2KE = hυ' + φ ……(ii)

or 2 (hυ + φ) = hυ' + φ

or υ' = 2υ + ⇒ υ' > 2υ