Question

Phenol treated with chloroform in presence of sodium hydroxide, which further hydrolysed in presence of an acid results

• A. Salicyclic acid
• B. Benzene-1,2-diol
• C. Benzene-1, 3-diol
• D. 2-Hydroxybenzaldehyde

Answer 1

Answer: (D)

2-Hydroxybenzaldehyde

Answer 2

The reaction of phenol with chloroform in the presence of sodium hydroxide, followed by hydrolysis in an acidic medium, is known as the Reimer-Tiemann reaction. This reaction results in the formation of 2-hydroxybenzaldehyde (commonly known as salicylaldehyde). The reaction can be represented as:
$\text{Phenol} + \text{CHCl}_3 + \text{NaOH} \rightarrow 2\text{-Hydroxybenzaldehyde (salicylaldehyde)}$

The reaction involves the introduction of a formyl group (-CHO) at the ortho position relative to the hydroxyl group (-OH), producing 2-hydroxybenzaldehyde.

The Correct Answer is: 2-Hydroxybenzaldehyde