QuestionReportQuestion: \(PH_{4}I + NaOH\) forms...PH4I+NaOHPH_{4}I + NaOHPH4I+NaOH formsAPH3PH_{3}PH3BNH3NH_{3}NH3CP4O6P_{4}O_{6}P4O6DP4O10P_{4}O_{10}P4O10AnswerPH3PH_{3}PH3