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Question

Chemistry Question on Colligative Properties

pH of a 0.1M0.1\, M monobasic acid is found to be 22. Hence, its osmotic pressure at a given temperature TKTK is

A

0.1 RT

B

0.11 RT

C

1.1 RT

D

0.01 RT

Answer

0.11 RT

Explanation

Solution

pH=2pH =2 [H+]=0.01M=Cx=0.1x\left[ H ^{+}\right]=0.01 \,M = Cx =0.1 x x=0.1x =0.1 i=1+x=1.1i =1+ x =1.1 π=inVRT=iMRT\pi=i \frac{n}{V} R T=i M R T =1.1×0.1RT=0.11RT=1.1 \times 0.1 \,R T=0.11 \,R T