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Question: Ph – CH2 – CH = CH2\(\xrightarrow { \text { dil. } \mathrm { H } _ { 2 } \mathrm { SO } _ { 4 } }\) ...

Ph – CH2 – CH = CH2→ dil. H2SO4\xrightarrow { \text { dil. } \mathrm { H } _ { 2 } \mathrm { SO } _ { 4 } } X,

Identify product 'X' is :

A

Ph – CH2 – CH2 – CH2 – OH

B

C

Ph−CH−CH2−CH3\mathrm { Ph } - \mathrm { CH } - \mathrm { CH } _ { 2 } - \mathrm { CH } _ { 3 } OH

D

Ph – CH2 – OH

Answer

Ph−CH−CH2−CH3\mathrm { Ph } - \mathrm { CH } - \mathrm { CH } _ { 2 } - \mathrm { CH } _ { 3 } OH

Explanation

Solution

Ph – CH2 – CH = CH2 →H+\xrightarrow { \mathrm { H } ^ { + } }Ph – CH2 – ⟶\longrightarrowPh – C⊖H\stackrel { \ominus } { \mathrm { C } } \mathrm { H } – CH2 – CH3 →H2O¨:\xrightarrow { \mathrm { H } _ { 2 } \ddot { \mathrm { O } } : }