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Question

Question: Period of \(\sin^{2}x\)is...

Period of sin2x\sin^{2}xis

A

π\pi

B

2π2\pi

C

π2\frac{\pi}{2}

D

None of these

Answer

π\pi

Explanation

Solution

sin2x=1cos2x2\sin^{2}x = \frac{1 - \cos 2x}{2} \Rightarrow Period =2π2=π.= \frac{2\pi}{2} = \pi.