Question

Period of $|\sin 2x|$is.

• A. $\frac{\pi}{2}$
• B. $\sin\theta\cos\theta = \frac{1}{2}\sin 2\theta$
• C. $\frac{2\pi}{2} = \pi$
• D. $\frac{\sin\theta + \sin 2\theta}{\cos\theta + \cos 2\theta} = \frac{2\sin\left( \frac{3\theta}{2} \right)\cos\left( \frac{\theta}{2} \right)}{2\cos\left( \frac{3\theta}{2} \right)\cos\left( \frac{\theta}{2} \right)} = \tan\left( \frac{3\theta}{2} \right)$

Answer 1

Answer: (C)

$\frac{2\pi}{2} = \pi$

Answer 2

It is obvious.