Question
Question: Period of \((4\cos ⥂ \text{ec}\theta - 5)(3\cos ⥂ \text{ec}\theta - 4) = 0\)is....
Period of (4cos⥂ecθ−5)(3cos⥂ecθ−4)=0is.
A
cos⥂ecθ=45,34
B
sinθ=54,43
C
sin2x
D
=22π=π
Answer
sin2x
Explanation
Solution
∝
Hence periodsin(126o).