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Question: Period of \((4\cos ⥂ \text{ec}\theta - 5)(3\cos ⥂ \text{ec}\theta - 4) = 0\)is....

Period of (4cos⥂ecθ5)(3cos⥂ecθ4)=0(4\cos ⥂ \text{ec}\theta - 5)(3\cos ⥂ \text{ec}\theta - 4) = 0is.

A

cos⥂ecθ=54,43\text{cos} ⥂ \text{ec}\theta = \frac{5}{4},\frac{4}{3}

B

sinθ=45,34\sin\theta = \frac{4}{5},\frac{3}{4}

C

sin2x\sin 2x

D

=2π2=π= \frac{2\pi}{2} = \pi

Answer

sin2x\sin 2x

Explanation

Solution

\propto

Hence periodsin(126o)\sin(126^{o}).