Question
Question: Period of \(12\cot^{2}\theta - 31\cos ⥂ ec\theta + 32 = 0\)is....
Period of 12cot2θ−31cos⥂ecθ+32=0is.
A
12(cos⥂ec2θ−1)−31cos⥂ec θ+32=0
B
12cos⥂ec2θ−31cos⥂ec θ+20=0
C
12cos⥂ec2θ−16cos⥂ec θ−15cos⥂ecθ+20=0
D
None of these
Answer
12cos⥂ec2θ−31cos⥂ec θ+20=0
Explanation
Solution
Since cos2A+cos2C=cos2A+cos2(2π−A). Hence period = =cos2A+sin2A=1.