Question

Percentage of Se (at. mass $=78.4$ ) in peroxidase anhydrase enzyme is $0.5 \%$ by weight, then minimum molecular mass of peroxidase anhydrase enzyme is

• A. $1.568 \times 10^3$
• B. $15.68$
• C. $2.168 \times 10^4$
• D. $1.568 \times 10^4$

Answer 1

Answer: (D)

$1.568 \times 10^4$

Answer 2

Suppose the molecular weight of enzyme = x 0.5% by weight means in 100 g of enzyme weight of Se = 0.5 g $\therefore$ In xg of enzyme weight of Se $\frac {0.5}{100} \times x$ Hence, $78.4 = \frac {0.5\times x}{100}$ $\therefore \, \, \, \, \, \, x = 15680 = 1.568 \times 10^4$