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Question: A complex $CrCl_3, 6H_2O$ gives violet color solution in one isomeric form and grey color solution i...

A complex CrCl3,6H2OCrCl_3, 6H_2O gives violet color solution in one isomeric form and grey color solution in another isomeric form These isomers are related as

A

[Cr(H2O)3Cl3].3H2O[Cr(H_2O)_3Cl_3].3H_2O

B

[Cr(H2O)4Cl2]Cl.2H2O[Cr(H_2O)_4Cl_2]Cl.2H_2O

C

[Cr(H2O)5Cl]Cl2.2H2O[Cr(H_2O)_5Cl]Cl_2.2H_2O

D

[Cr(H2O)6]Cl3[Cr(H_2O)_6]Cl_3

Answer

[Cr(H2O)6]Cl3[Cr(H_2O)_6]Cl_3

Explanation

Solution

The complex CrCl3⋅6H2OCrCl_3 \cdot 6H_2O exhibits hydration isomerism. The isomer [Cr(H2O)6]Cl3[Cr(H_2O)_6]Cl_3 is known to be violet, as all six water molecules are coordinated to the chromium ion. Other isomers, like [Cr(H2O)4Cl2]Cl⋅2H2O[Cr(H_2O)_4Cl_2]Cl \cdot 2H_2O (dark green) and [Cr(H2O)3Cl3]⋅3H2O[Cr(H_2O)_3Cl_3] \cdot 3H_2O (green/grey-green), exist. Option D correctly identifies the violet isomer. Option C is incorrect as it contains 7 water molecules. Options A and B are valid isomers but represent the green/grey forms. Given that one form is violet and the options are specific formulas, the violet form (Option D) is the most distinct and primary candidate among the choices.