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Question

Quantitative Ability and Data Interpretation Question on SI & CI

Pawan borrowed Rs. 30,000 from a greedy money lender for a certain rate of compound interest and agreed to return it after 1 year. As he could not pay it at the end of the year, the interest rate was increased by 10%. As Pawan could not pay the debt the second year, the money lender increased the interest rate by another 20%. If Pawan closed the loan by paying an interest of Rs. 33590.625 at the end of the third year, find the initial interest rate.

A

15%

B

20%

C

25%

D

30%

E

33.33%

Answer

25%

Explanation

Solution

Let the initial interest rate be r%r\%.

Interest rate for the second year = (1+10%)r%=1.1r%(1+10\%)r\% = 1.1r\%

Interest rate for the third year = (1+20%)1.1r%=1.32r%(1+20\%)1.1r\% = 1.32r\%

Then, 30,000+33590.625=30,000(1+r%)(1+1.1r%)(1+1.32r%)30,000 + 33590.625 = 30,000(1+r\%)(1+1.1r\%)(1+1.32r\%)

63590.62530000=(211.96100)=(1+r%)(1+1.1r%)(1+1.32r%)\frac{63590.625}{30000} = \bigg(\frac{211.96}{100}\bigg) = (1+r\%)(1+1.1r\%)(1+1.32r\%)

Using options:

Option A: (1+15%)(1+16.5%)(1+19.8%)=160.5100(1+15\%)(1+16.5\%)(1+19.8\%) = \frac{160.5}{100}

Option B: (1+20%)(1+22%)(1+26.4%)=185.04100(1+20\%)(1+22\%)(1+26.4\%) = \frac{185.04}{100}

Option C: (1+25%)(1+27.5%)(1+33%)=211.96100(1+25\%)(1+27.5\%)(1+33\%) = \frac{211.96}{100}

Hence, option C is the correct answer.