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Question: A loop of light inextensible string passes over smooth small pulleys A and B. Two masses m and M are...

A loop of light inextensible string passes over smooth small pulleys A and B. Two masses m and M are attached to the points O and C respectively. Then the condition that m and M will cross each other is: [Take: AB = 2l and AC = AB = ηl]

A

2 -1

B

2 -1

C

M η+3

D

none of these

Answer

(B)

Explanation

Solution

The condition for the masses to cross each other is related to the stability of the system and can be derived by analyzing the potential energy. The correct condition is:

mM>2η+3η+11\frac{m}{M} > 2\sqrt{\frac{\eta+3}{\eta+1}}-1