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Question: Parallel beam of light is incident on a concave mirror with radius of curvature \(\sqrt { 2 }\) m w...

Parallel beam of light is incident on a concave mirror with radius of curvature 2\sqrt { 2 } m which is subtending an angle 90° at C. The length on principal axis illuminated by reflected light –

A

(112)\left( 1 - \frac { 1 } { \sqrt { 2 } } \right)m

B

2(112)\sqrt { 2 } \left( 1 - \frac { 1 } { \sqrt { 2 } } \right)

C

(1+12)\left( 1 + \frac { 1 } { \sqrt { 2 } } \right)

D

None of these

Answer

(112)\left( 1 - \frac { 1 } { \sqrt { 2 } } \right)m

Explanation

Solution

length ilhuminated = x – f = R2\frac { \mathrm { R } } { 2 }

= R2\frac { \mathrm { R } } { \sqrt { 2 } }R2\frac { \mathrm { R } } { 2 } = (112)\left( 1 - \frac { 1 } { \sqrt { 2 } } \right)m