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Question

Physics Question on laws of motion

P,QP, Q and RR are three coplanar forces acting at a point and are in equilibium. Given P=1.9318kgwtP=1.9318\, kg\, wt [sinθ1=0.9659]\left[\sin \theta_{1}=0.9659\right], the value of RR (in kgkg wt) is

A

0.9659

B

2

C

1

D

44563

Answer

1

Explanation

Solution

Using Lami's theorem, we have Psinθ1=Rsin150\frac{P}{\sin \theta_{1}}=\frac{R}{\sin 150^{\circ}} Psinθ1=Rsin(18030)\Rightarrow \frac{P}{\sin \theta_{1}}=\frac{R}{\sin \left(180^{\circ}-30^{\circ}\right)} 1.9318kgwt0.9659=R1/2\Rightarrow \frac{1.9318\, kg wt}{0.9659}=\frac{R}{1/2} R=1.93180.9659×12kgwt=1kgwt.\Rightarrow R=\frac{1.9318}{0.9659}\times\frac{1}{2}\,kg\,wt = 1\, kg\,wt.