Question

P is any point on the ellipse 81x² +144y² = 1944 whose foci are S and S¢ then SP +S¢P=

• A. 3
• B. 4$\sqrt{6}$
• C. 36
• D. 324

Answer 1

Answer: (B)

4$\sqrt{6}$

Answer 2

$\frac{81x^{2}}{1944}$+ $\frac{144y^{2}}{1944}$= 1 Ž $\frac{x^{2}}{24}$+ $\frac{4y^{2}}{54}$= 1