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Question: P is a point on the side BC of the \(\Delta ABC\) and Q is a point such that \(\overset{\rightarrow}...

P is a point on the side BC of the ΔABC\Delta ABC and Q is a point such that PQ\overset{\rightarrow}{PQ} is the resultant of AP,PB,PC.\overset{\rightarrow}{AP},\overset{\rightarrow}{PB},\overset{\rightarrow}{PC}. Then ABQC is a

A

Square

B

Rectangle

C

Parallelogram

D

Trapezium

Answer

Parallelogram

Explanation

Solution

AP+PB+PC=PQ\overset{\rightarrow}{AP} + \overset{\rightarrow}{PB} + \overset{\rightarrow}{PC} = \overset{\rightarrow}{PQ} or AP+PB=PQ+CP\overset{\rightarrow}{AP} + \overset{\rightarrow}{PB} = \overset{\rightarrow}{PQ} + \overset{\rightarrow}{CP}

or AB=CQ\overset{\rightarrow}{AB} = \overset{\rightarrow}{CQ}.

Hence it is a parallelogram.