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Question: P and Q are points on the line joining A (­–2, 5) and B (3, 1) such that AP = PQ = QB. Then the mid-...

P and Q are points on the line joining A (­–2, 5) and B (3, 1) such that AP = PQ = QB. Then the mid-point of PQ is.

A

(12,3)\left( \frac{1}{2},3 \right)

B

(12,4)\left( - \frac{1}{2},4 \right)

C

(2,3)(2,3)

D

(1,4)(1,4)

Answer

(12,3)\left( \frac{1}{2},3 \right)

Explanation

Solution

Mid-point of PQ is the same as that of AB in view of the given conditions i.e., (12,3)\left( \frac { 1 } { 2 } , 3 \right) .