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Question

Chemistry Question on Molecular Orbital Theory

Oxygen molecule is paramagnetic in nature. What is the paramagnetic content in terms of magnetic moment in O2O^{-}_{2}?

A

1.7321.732

B

33

C

1.51.5

D

2.52.5

Answer

1.7321.732

Explanation

Solution

O2:(σ1s2)(σ1s2)(σ2s2)(σ2s2)(σ2Pz2)O_{2}^{-} : \left(\sigma 1s^{2}\right)\left(\sigma^* 1s^{2}\right)\left(\sigma 2s^{2}\right)\left(\sigma^* 2s^{2}\right) \left(\sigma 2P_{z}^{2}\right) (π2px2=π2py2)(π2px2=π2py1)\left(\pi 2p_{x}^{2} = \pi2p_{y}^{2}\right) \left(\pi^{ *} 2p_{x}^{2} = \pi^{ *} 2p_{y}^{1}\right) O2O_{2}^{-} has 11 unpaired electron. μ=n(n+2)B.M.\mu=\sqrt{n\left(n+2\right)}B.M. =1(1+2)=3= \sqrt{1\left(1+2\right)} = \sqrt{3} =1.732B.M.= 1.732 B.M.