Question

Oxygen has an oxidation state of +2 in the compound :

• A. $\ce{H_2O_2}$
• B. $\ce{CO_2}$
• C. $\ce{H_2O}$
• D. $\ce{F_2O}$

Answer 1

Answer: (D)

$\ce{F_2O}$

Answer 2

In $H_2O_2 : \Rightarrow 2 \times (+1) + 2 \times x = 0$ $\Rightarrow \, x = - 1$ In $CO_2 : \Rightarrow 4 + 2 x = 0 \Rightarrow x = - 2$ In $H_2O : \Rightarrow 2 \times (+1) + x = 0 \Rightarrow x =- 2$ In $F_2O :\Rightarrow 2 \times (-1) + x = 0 \Rightarrow x= + 2$