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Question: Oxygen boils at \(-{{183}^{\circ }}C\) . This temperature in Fahrenheit scale is approximately: \[...

Oxygen boils at 183C-{{183}^{\circ }}C . This temperature in Fahrenheit scale is approximately:

& A){{215}^{\circ }}F \\\ & B)-{{297.4}^{\circ }}F \\\ & C){{329}^{\circ }}F \\\ & D)361{{~}^{\circ }}F \\\ \end{aligned}$$
Explanation

Solution

We used a formula to relate the temperatures of Fahrenheit scale to that of the absolute scale. We can consider two different sets of temperatures that provide us with two equations. A temperature scale is defined by choosing two fixed points whose values are easily reproduced. In the case of the Celsius scale, the lower point is the melting point of pure ice at normal atmospheric pressure and the upper fixed point is the boiling point of pure water at normal atmospheric pressure.

Formula used: Tf=TC×95+32{{T}_{f}}={{T}_{C}}\times \dfrac{9}{5}+32

Complete step by step answer:
We know that a temperature scale is a unit of measurement to measure the temperature. Usually, scales of temperature are developed by first fixing points. The temperature values of these two limits must be easily reproducible by some natural phenomenon. Then the scale is calibrated by making equal divisions between these two limits. Let us consider Tf{{T}_{f}} to be the temperature of water in Fahrenheit scale and TC{{T}_{C}} to be the temperature on the celsius.
TC{{T}_{C}} given to us is 183C-{{183}^{\circ }}C.
Now, we can relate both the scales together by,
Tf=TC×95+32 Tf=183×95+32=361.4F \begin{aligned} & {{T}_{f}}={{T}_{C}}\times \dfrac{9}{5}+32 \\\ & \Rightarrow {{T}_{f}}=-183\times \dfrac{9}{5}+32={{361.4}^{\circ }}F \\\ \end{aligned}
So, the given temperature in Fahrenheit scale is found to be 361.4F{{361.4}^{\circ }}F.

So, the correct answer is “Option D”.

Note: We need to analyze the requirement and the data that the question provides. In thermodynamics, the triple point of a substance is the temperature and pressure at which the three phases of that substance i.e., solid, liquid and gas coexist in thermodynamic equilibrium. In the phase diagram, the point where the sublimation curve, fusion curve and the vaporization curve meet, its temperature and pressure is known as the triple point. For example, the triple point of mercury occurs at a pressure of 0.2 mPa and at a temperature of 38.83440C-{{38.83440}^{\circ }}C .