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Question

Physics Question on Kinetic molecular theory of gases

Oxygen and hydrogen are at the same temperature TT . The ratio of the mean kinetic energy of oxygen molecules to that of the hydrogen molecules will be

A

16:116 : 1

B

1:11: 1

C

4:14 : 1

D

1:41 : 4

Answer

1:11: 1

Explanation

Solution

The mean kinetic energy for gas molecules
E=32KTE=\frac{3}{2}KT
ET\Rightarrow E \propto T
So, E1E2=T1T2(i)\frac{E_{1}}{E_{2}}=\frac{T_{1}}{T_{2}} \ldots\left(i\right)
According to question both the gases are at the same temperature TT
So, E1E2=TT=11\frac{E_{1}}{E_{2}}=\frac{T}{T}=\frac{1}{1}
E1:E2\Rightarrow E_{1} : E_{2}
=1:1=1:1