Question
Question: Oxygen and cyclopropane at partial pressure of \(570{\text{ }}torr\) and \(170{\text{ }}torr\) respe...
Oxygen and cyclopropane at partial pressure of 570 torr and 170 torr respectively are mixed in a gas cylinder. What is the ratio of the number of moles of cyclopropane to the number of moles of oxygen?
A. 740170=0.23 B. 42170/[42170+32570]=0.19 C. 570×32170×42=0.39 D. 570170=0.30Solution
Hint- In order to deal with this question first we will write the ideal gas equation for cyclopropane and oxygen then we will get the relation between the number of moles and pressure further by putting the values and taking the values of temperature and volume constant we will get the answer.
Complete step-by-step answer:
Formula used- pV=nRT
Given that
Partial pressure exerted by cyclopropane =170 torr.
Partial pressure exerted by oxygen =570 torr.
We know that ideal gas equation is given as
pV=nRT
Here p is the pressure, V is the volume of gas, n is the number of moles of gas, T is the temperature of the gas and R is the gas constant.
Let us consider cyclopropane as case (1)
p1V=n1RT
Now consider case of oxygen as case (2)
p2V=n2RT
Assuming volume and temperature constant in the above two equations and taking the ratio of case (1) and case (2) we get:
⇒p2Vp1V=n2RTn1RT ⇒p2p1=n2n1
Thus, substituting the values of given pressure in the above equation we get:
∵p2p1=n2n1 ⇒n2n1=570torr170torr ⇒n2n1=570170=0.3
Hence, the ratio of the number of moles of cyclopropane to the number of moles of oxygen is 0.3
So, the correct answer is option D.
Note- The ideal gas formula, also known as the general gas equation, is the equation of state of an ideal imaginary gas. This is a good approximation of other gases' behavior under several circumstances, but it has many drawbacks.