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Question: Oxyacids of phosphorus and the starting material for their preparation are given below. \[Oxy...

Oxyacids of phosphorus and the starting material for their preparation are given below.

OxyacidsOxyacidsMaterial for preparationMaterial{\text{ }}for{\text{ }}preparation
A. H3PO2A.{\text{ }}{H_3}P{O_2}(i) Red P + alkali\left( i \right){\text{ }}Red{\text{ }}P{\text{ }} + {\text{ }}alkali
B. H3PO3B.{\text{ }}{H_3}P{O_3}(ii) P4O10+ H2O\left( {ii} \right){\text{ }}{P_4}{O_{10}} + {\text{ }}{H_2}O
C. H3PO4C.{\text{ }}{H_3}P{O_4}(iii) P2O3+ H2O\left( {iii} \right){\text{ }}{P_2}{O_3} + {\text{ }}{H_2}O
D. H4P2O6D.{\text{ }}{H_4}{P_2}{O_6}(iv) White P + alkali\left( {iv} \right){\text{ }}White{\text{ }}P{\text{ }} + {\text{ }}alkali

Choose the correct answer from the quotes given;
(A) A(iv); B(iii); C(ii); D(i)\left( A \right){\text{ }}A - \left( {iv} \right);{\text{ }}B - \left( {iii} \right);{\text{ }}C - \left( ii \right);{\text{ }}D - \left( {i} \right)
(B) A(i); B(iii); C(ii); D(iv)                                                                                \left( B \right){\text{ }}A - \left( i \right);{\text{ }}B - \left( {iii} \right);{\text{ }}C - \left( {ii} \right);{\text{ }}D - \left( {iv} \right)\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;
(C) A(iv); B(iii); C(i); D(ii)\left( C \right){\text{ }}A - \left( {iv} \right);{\text{ }}B - \left( {iii} \right);{\text{ }}C - \left( i \right);{\text{ }}D - \left( {ii} \right)
(D) A(ii); B(iii); C(i); D(iv)\left( D \right){\text{ }}A - \left( {ii} \right);{\text{ }}B - \left( {iii} \right);{\text{ }}C - \left( i \right);{\text{ }}D - \left( {iv} \right)

Explanation

Solution

The oxoacids are those acids which contain oxygen. Phosphorous is known to form oxyacids such as, H3PO4{H_3}P{O_4} ,H3PO3{H_3}P{O_3},H3PO2{H_3}P{O_2} , etc. The phosphorus in oxoacid is tetrahedral surrounded by atoms. Mostly, these all acids are having at least one P=OP = O and one POHP - OH bond. An oxoacid, oxyacid or ternary acid is an acid that has oxygen.

Complete step-by-step answer:
These acids are found to be disproportionate to either lower or higher oxidation states. For example, when phosphorous acid is heated, it produces phosphine and phosphoric acid.
4H3PO33H3PO4+PH34{H_3}P{O_3}\, \to \,3{H_3}P{O_4}\, + \,P{H_3}

Phosphorous acid, H3PO3{H_3}P{O_3}: H3PO3{H_3}P{O_3} is a diprotic acid. It ionizes two protons. It is described with the structural formula HPO(OH)2HPO{\left( {OH} \right)_2} . When the hydrolysis occurs with phosphorus trichloride in the presence of acid or steam it forms H3PO3{H_3}P{O_3} .
PCl3  +  3  H2O    HPO(OH)2  +  3  HClPC{l_3}\; + \;3\;{H_2}O\; \to \;HPO{(OH)_2}\; + \;3\;HCl
P2O3 + 3H2O2H3PO3(Phosphorusacid){P_2}{O_3}\,{\text{ + }}\,3{H_2}O\, \to \,\,2{H_3}P{O_3}\,(\,Phosphorus\,acid)

Phosphoric acid, H3PO4{H_3}P{O_4}: H3PO4{H_3}P{O_4} is a triprotic acid. It ionizes three protons. It is also non-toxic acid when it is pure, solid at room temperature and pressure. When sulphuric acid is added to tricalcium phosphate rock it forms phosphoric acid.
Ca5(PO4)3X  +  5  H2SO4  +  10  H2O    3H3PO4  +  5  CaSO4.2H2O  +  HXC{a_5}{(P{O_4})_3}X\; + \;5\;{H_2}S{O_4}\; + \;10\;{H_2}O\; \to \;3{H_3}P{O_4}\; + \;5\;CaS{O_4}.2{H_2}O\; + \;HX
X=F,Cl,BrandOHX = \,F,\,Cl,\,Br\,and\,OH
P4O10+6H2OH4PO4(phosphoricacid){P_4}{O_{10}}\, + \,\,6{H_2}O\,\, \to \,\,{H_4}P{O_4}\,(phosphoric\,acid)

Hypophosphorous acid, H3PO2{H_3}P{O_2}: H3PO2{H_3}P{O_2} is produced when white phosphorous treated with alkali solution to produce H3PO2{H_3}P{O_2}.
WhiteP + AlkaliproducesH3PO2{\text{White}}\,{\text{P}}\,{\text{ + }}\,{\text{Alkali}}\,{\text{produces}}\,\,{H_3}P{O_2}

Hypophosphoric acid, H4P2O6{H_4}{P_2}{O_6}: H4P2O6{H_4}{P_2}{O_6} is an acid of tetrabasic. It is formed by conduction of the controlled oxidation of red phosphorus with sodium chlorite. When the disodium salt is formed it gives hypophosphoric acid H4P2O6{H_4}{P_2}{O_6} via cation exchanger.
2P + 2NaClO2  + 2H2O  Na2H2P2O6  + 2HCl2P{\text{ }} + {\text{ }}2NaCl{O_2}\; + {\text{ }}2{H_2}O{\text{ }} \to {\text{ }}N{a_2}{H_2}{P_2}{O_6}\; + {\text{ }}2HCl
Na2H2P2O6  + 2Hresin H4P2O6  + 2Na  resinN{a_2}{H_2}{P_2}{O_6}\; + {\text{ }}2H\,\, \to \,resin\,\, \to {\text{ }}{H_4}{P_2}{O_6}\; + {\text{ }}2Na{\text{ }}-{\text{ }}resin

Therefore, the answer is,
WhiteP + AlkaliproducesH3PO2{\text{White}}\,{\text{P}}\,{\text{ + }}\,{\text{Alkali}}\,{\text{produces}}\,\,{H_3}P{O_2}
P2O3 + 3H2O2H3PO3(Phosphorusacid){P_2}{O_3}\,{\text{ + }}\,3{H_2}O\, \to \,\,2{H_3}P{O_3}\,(\,Phosphorus\,acid)
P4O10+6H2OH4PO4(phosphoricacid){P_4}{O_{10}}\, + \,6{H_2}O\, \to \,{H_4}P{O_4}(phosphoric\,acid)
RedP + AlkaliproducesH4P2O6{\text{Red}}\,{\text{P}}\,{\text{ + }}\,{\text{Alkali}}\,{\text{produces}}\,\,{H_4}{P_2}{O_6}

So, the correct option is ‘A’.

Note: MetaPhosphoric, (HPO3)n(HP{O_3})n: when orthophosphoric acid is warmed around 860 K860{\text{ }}K
the formation of meta phosphoric acid takes place. These exist in cyclic trimers, etc.
H3PO4   HPO3  + H2O{H_3}P{O_4}\; \to {\text{ }}HP{O_3}\; + {\text{ }}{H_2}O
There are more oxoacids, oxyacids.