Question

Oxidation state of sulphur in $S _{8}, H _{2} S$ and $S _{2} F _{2}$ is

• A. 0, -2, -1
• B. 0, +2, -1
• C. 1, -2, +1
• D. 0, -2, +1

Answer 1

Answer: (D)

0, -2, +1

Answer 2

Oxidation state of S in S = 0 Oxidation state of S in HS $\Rightarrow$ +2 + x = 0 $\Rightarrow$ x = -2 Oxidation state of S in SF $\Rightarrow$ 2x + 2(-1) = 0 $\Rightarrow$ x = + 1