Question

Oxidation state of S in $H_{2}S_{2}O_{8}$is.

• A. +6
• B.
  • 7
• C.
  • 8
• D. 0

Answer 1

Answer: (A)

+6

Answer 2

: $H_{2}S_{2}O_{8}$

Two oxygen atoms are involved in peroxide linkage, hence oxidation number will be – 1 (each)

$H_{2}S_{2}O_{8} = \underset{H}{2( + 1)} + 2\underset{S}{(x)} + \underset{O - O}{2( - 1)} + 6\underset{O}{( - 2)} = 0$

x = +6