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Question

Chemistry Question on Classification of elements & periodicity in properties

Oxidation state of oxygen in OF2OF_{2} and Na2ONa_{2}O is +2+2 and 2-2 respectively. Oxygen is an electronegative element.

A

If both assertion and reason are true and reason is the correct explanation of assertion.

B

If both assertion and reason are true but reason is not the correct explanation of assertion.

C

If assertion is true but reason is false.

D

If both assertion and reason are false.

Answer

If both assertion and reason are true but reason is not the correct explanation of assertion.

Explanation

Solution

The electronegativity order of three elements involved in these compounds is F>O>NaF > O > Na. Hence in OF2OF _{2} molecule, FF is more electronegative than OO, element FF is given oxidation state 1-1 and thus, OO shows +2+2 oxidation state. On the other hand, in Na2O,ONa _{2} O , O is more electronegative than NaNa, hence, NaNa is given +1+1 oxidation state and OO shows oxidation state 2-2.