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Question

Chemistry Question on Oxidation Number

Oxidation state of FeFe in Fe3O4 isFe_3O_4 \, is

A

32\frac {3}{2}

B

45\frac {4}{5}

C

54\frac {5}{4}

D

83\frac{8}{3}

Answer

83\frac{8}{3}

Explanation

Solution

Let the oxidation state of FeF e be xx ⇒3x+4(−2)=0\Rightarrow 3 x+4(-2)=0 ⇒x=+83\Rightarrow x=+\frac{8}{3}