Question

Oxidation state of Cl in $CaOCl_2$ is/are

• A. Zero
• B. 1
• C. -1
• D. #ERROR!

Answer 1

Answer: (D)

#ERROR!

Answer 2

$CaOCI_2$ is actually $Ca^{2+} (OCI)^{+1^-}CI^{-1^-}$ =O.N of two Cl atoms are +1 and -1