Question

Oxidation state of carbon in diamond is:
(A) Zero
(B) $+ 1$
(C) $- 1$
(D) $+ 2$

Answer 1

Carbon is an element denoted by the symbol $C$. It is the most important element in chemistry. This element is present in the group $14$ in periodic table. It belongs to the p block.

Complete step by step answer:
- In the universe carbon is found in a very large amount. It is also found in the human body in a very large amount (second most abundant after oxygen). Atomic carbon is very less stable in an elemental state so it is mostly present in molecular form. According to carbon molecular configuration in a very large number carbon atoms combine with each other to form molecules. This molecular form has a different molecular configuration known as allotropes.
- Mainly Carbon are two types on the basis of their structure- crystalline and amorphous. Amorphous forms of carbon that are present in nature that is Diamond, Graphite. And the amorphous form of carbon is Coal, lamp black, charcoal.
- Oxidation state of carbon ($C$) is different in different forms. In diamond carbon is present in nature in elemental form so oxidation of carbon in diamond is $0$.
The correct answer is option “A” .

Note: The atomic weight of Carbon is $6g/mol$. The molecular heat capacity is different in different forms of carbon. The molecular heat capacity in diamond $8.517j/mol/k$ and the molecular heat capacity in diamond $6.155j/mol/k$.
- Carbon have three isotopes (isotopes may be defined as the elemental form of an element having carry same atomic number but having different atomic mass)${C^{12}}$,${C^{13}}$,${C^{14}}$.
- Diamonds have cubic structure and the shape of the diamond is octahedral. Diamond is very hard due to this hardness it is very useful in drilling machines.