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Question

Chemistry Question on Electrolysis

Oxidation of succinate ion produces ethylene and carbon dioxide gases. On passing 0.20.2 Faraday electricity through an aqueous solution of potassium succinate, the total volume of gases (at both cathode and anode) at STP (1atm1\, atm and 273K273\, K) is :

A

2.24L2.24\, L

B

4.48L4.48\, L

C

6.72L6.72\, L

D

8.96L8.96\, L

Answer

8.96L8.96\, L

Explanation

Solution

Total equivalents of C2H4+CO2+H2=0.2+0.2+0.2=0.6C_{2}H_{4}+CO_{2}+H_{2} = 0.2+0.2+0.2 = 0.6 Total moles of gases =0.22+0.21+0.22=0.4= \frac{0.2}{2}+\frac{0.2}{1}+\frac{0.2}{2} = 0.4 v=nRTP=0.4×0.0821×2731v = \frac{nRT}{P} = \frac{0.4\times0.0821\times273}{1} =8.96L= 8.96\,L